==========================udddalakbanerjee(ubj)
###this is based on real life incident..and each of the dialogues are real ones that took place between ubj and the interviewer from CTS.
THE INTERVIEW WAS TAKING PLACE AFTER 7:30 AT NIGHT .My panel no was 6 .There were about 158 people shortlisted after the written test.Interview was taking place in alphabetical order so my name came at 19th in my panel and it was really late and I was growing very restless.Anyways finally the call to go in came.
INTERVIEWER,”COME IN ..”
UBJ,”GOOD AFTERNOON SIR..”
INTERVIEWER,”TAKE YOUR SEAT..”
UBJ,”SIR THIS IS A BOOK THAT I HAVE WRITTEN ..THIS CONTAINS POEMS AND SHORTSTORIES WHICH ARE TO BE PUBLISHED SOON IN A LEADING MAGAZINE IN THE WORLD.”
INTERVIEWER,”HMM..what does this J MEAN?”
UBJ,”SORRY SIR COULD NOT GET U .”
INTERVIEWER,”U HAVE WRITTEN UBJ ..YOUR NAME IS UDDALAK BANERJEE SO IT UB ..SO WHAT IS THIS J FOR?”
UBJ,”JEN X”
INTERVIEWER,”SO THEN..TELL ME SOMETHING ABOUT YOURSELF”
UBJ,”I AM A ROCKING HONEST AND SIMPLE PERSON WHO MAKES LIFE WORTH LIVING .i WRITE BECAUSE IT IS MY HOBBY AND FIND FULFILLMENT IN IT.I AM VERY DIRECT IN MY APPROACH AND I LOVE TO PAINT TOO.MY MOM AND DAD ARE IN BANKS AND I BEING THEIR ONLY SON AHD DEDICATED MY LIFE FOR COMPUTER ENGG AND WRITING.I HAVE A LOT OF FRIENDS AND FANS BOTH AND I LOVE THEM VERY MUCH.”
INTERVIEWER,”WHICH LANGUAGES DO YOU KNOW?”
UBJ,” WELL I know languages C,C++,VB.Net,Java,shell scripting etc..but I know them all in elementary levels only ..Actually if I say that I know these languages…it means that I know them to the fullest which again Is perhaps impossible because the ambit of these languages is very huge and to know every function is redundant for any one may be.It is impossible to learn any language to the fullest.”
INTERVIEWER,”DEFINE A STRUCTURE AND WRITE A CODE IN C FOR STRUCTURE”
UBJ,”Structure is a memory block that is used to store data of similar interreleated types.Code for structure would be
Struct C
{
Int I ;
Char c;
Float f;
}
To call:
From main :
Struct C a,b,c …and so on.;
A,b,c are structures of the type C
INTERVIEWER ,”TELL ME THE MAX APPLICATION U KNOW OF C?”
Ubj,”rockets can be launched using C .We can make functions and modules for the same.”
INTERVIEWER,”ILLUSTRATE”
UBJ,”the entire rocket launch sequence is based on the primitive equation p=mv and we need to go on differentiating this equation .but yes in C WE DON’T have any such differentiation function so we have to create functions separately to calculate float values of minor differences with a loop of time to minitor minor changes.Now then we have to break the whole thing into modules.There would be modules for propeller speed,module to calculate air drag and backward thrust exerted by air and also speed variation factor based on climate and then there would be distance calculation function that would calculate distance from earth.Apart from all this there would be a module on air density and temperature calculation which would take data from the sensors fitted on the body of the rocket and this function will be called ever pico second.With C being a middle level language all this possible because it interacts with hardware.
Interviewer,”So then tell me about hobbies now..if I give u a choice between programming and writing which one will u choose ?”
UBJ,”WRITING and not programming”
Interviewer,”why ?”
UBJ,”BECAUSE I am popular with this and I believe that I write well and now that I am beginning to get to people whom I have never met or seen I don’t want to leave this medium.
Interviewer ,”but !!ok leave it”(looks through the book)
Interviewer,”you write well..but will this give you enough living?”
UBJ,”I DON’T KNOW BUT YES ONE THING IS FOR SURE I LOVE IT.”
Interviewer,”what is ubj inventions?tell me something on this”
UBJ,”when I was in school I wanted to calculate rather extrapolate values of pi from mechanics using different values of constants and I tried hard and found various values and I have enumareted the values and methods used in these blogs.I have done some papers on AI too so that is again a part of ubj inventions.”
Interviewer,”ok but now tell me inventions or writing which will u prefer”
UBJ,”writing sir..it is part of documentation process .I love it.”
Interviewer,”ok then.It had been a pleasure meeting you.” (flips through the pages of the book)
Interviewer,”nice work someday u may be a great writer.”
UBj,”thank you sir”
Interviewer,”next”
==============================================================
Technical innovation is a tool for human potential harnessing OR is human potential harnessing is a tool for technical innovation?My learnings of Computer Science engineering from NIT coupled with my drive for Human potential enhancement.
Saturday, April 17, 2010
cts interview
Life is a differentiation of dreams which is in terms of education multiplied with effort and innovation
UBJ ‘S SUPER INTERVIEW CRACK QUESTIONS
THE FOLLOWING SETS OF QUESTIONS WHICH ARE GIVEN BELOW WILL HELP YOU TO CLEAR ANY INTERVIEW OF ANY TECHNICAL LEVEL.APART FROM THIS MAKE SURE THAT U HAVE ALREADY READ THE TWO INTERVIEW QUESTIONS I HAD ALREADY UPLOADED OF PERSISTENT AND BIRLASOFT .
============================================UDDALAK BANERJEE(UBJ),CSE ,NIT RAIPUR .
Q.WHAT IS A RESULTSET ?
ANS:IT IS AN INTERFACE IN JAVA which is used to store data on execution of query.
Q.What is white box testing?
Ans:IT is close examination of procedural detail.
Q.what is alpha testing?
Ans: IT is conducted at developer’s site by end users.
It is conducted in controlled environment.
Q.What is beta testing?
Ans:IT is conducted at enduser sites.
Developer is not present here.
Q.what is blackbox testing?
Ans:Examines some fundamental aspects of a system with little regard for the internal logical software of the software.
Q what are DiskScheduling methods?
Ans: FCFS
SSTF
SCAN
LOOK
Q.what is critical section problem?
Ans: TO design a protocol that the processes can use to cooperate.
Critical section is segment of code in which process may be changing common variables,updating tables etc
QWhat is the solution to critical section problem?
Ans: 1.Mutual Exclusion
2.Progress Requirement
3.Bounded Waiting
Q.write PreOrder,postoder and inorder Traversal of the following tree.
A,B,C,D,E ,F,G,H,I
ANS: PREORDER: A B D G C E H I F
POSTORDER: G D B H I E F C A
INORDER: D G B A H E I C F
Q what are the orders of traversal ?
Ans: Post Order: Left Right Root
INorder: Left Root Right
Preorder: Root left right
Q.What is ALOHA?
ANS: IT is earliest random access method(in early 1970s)
It is of two types-
1.Pure ALOHA
2.Slotted ALOHA
Q.what is thoroughput for pure ALOHA?
Ans:S=g* e^-2g
Where
Smax=0.184
When G=0.5
Vulnerable time=2*Tfr
Q.what is throughput for slotted ALOHA?
Ans: S=g*e^-g
Smax=0.368
G=1
Vulnerable time=Tfr
Q.what is SNR?
Ans: It is called Signal to Noise Ratio
Snr= AVERAGE SIGNAL POWER/AVERAGE NOISE POWER
Q what are networking commands in LINUX?
Ans: LYNX --- browse from ordinary terminal
DU---- DISK USAGE OF FILES AND DIRECTORIES IN FILENAME
WHO AM I – RETURN USERNAME
TALK USERNAME--- LETS CONVERSATION WITH OTHER USER
WRITE USERNAME--- EXCHANGE ONLINE MESSAGES
FF---- FINDS FILENAME ON SYSTEM
GREP STRING,FILENAME----- LOOKS FOR STRING IN FILENAME
RLOGIN HOSTNAME--- CONNECTS TO REMOTE HOST
Q.WHAT ARE Java Server Faces specification?
Ans: Packages are:
Javax.faces
Javax.faces.convert------- interfaces defining converter
Javax.faces.event---------interfaces define event file
Javax.faces.webapp------classes required for integration of java server file.
Q.what is full form of ICAD?
Ans: Internet Content Adapter Protocol.
Q.Write a simple if loop in linux?
Ans: echo $ ubj=:uddalak banerjee”
If [ -z “$ ubj”]
Myname= ‘ who am I ‘
Fi
Q. What is Unit testing?
ANs :IT focuses verification effort on the smallest unit of software design—the software components of modules.
Boundary testing is one of the most important unit testing tasks
Unit tests should uncover errors such as the following :
1.comparison of different datatypes
2.incorrect logical operator or precedence
3.incorrect comparison of variables
4.improper loop termination.
Q. What are the disadvantages of water fall model?
ANs: 1.Real Life Projects donot follow sequential flow
2.Customer has to state all requirements first
Q.what are the advantages of spiral model?
ANs: 1.realistic approach
2.Uses prototypes as risk reduction.
Q.what is data transformation?
ANs: Data is transformed into other forms appropriate for mining.
Data transformation involves—
1.smoothing
2.Aggregation
3.Generalization
4.Normalization
5.Attribute Construction
Q What are different Datamodels?
ANs 1.semistructured
2.Object Oriented
3. object relational
4.ER
Q.what are types of Databases?
Ans 1.temporal
2.Sequence Database
3.time series Database
4.Spatial Database
5.Spatial Temporal Database
6.Text Database
7.Multimedia Database
Q. What are techniques used to remove noise?
Ans : 1.Binning
2.Regression
3.Clustering
Q.what is Build?
ANs: Process of converting source code into executable code given to testing
Q.what is change control?
Ans:Change Management Process involves technical change analysis .Cost Benefit analysis and change tracking.
Q.What are key factors considered by a board in making decisions on change?
ANs: 1.size of change
2. complexity of change
3. related systems
4.data when it is needed
5.impact on current and subsequent work
6.cost
7.possible alternatives
Q.what is SCM STANDARD?
ANS: ANSI IEEE 823-1983-1042-1028
Q.What Is demand paging?
ANs: O S copies a diskpage into physical memory only if an attempt is made to access it ( that is if page fault occurs)
Q.WHAT ARE THE DISADVANTAGES OF DEMAND PAGING?
ANS: 1.MEMORY MANAGEMENT with page replacement algorithm becames more challenging
2.Individual programs face extra latency
Q. what is a dispatcher?
Ans:1.Long term scheduler
Decides which job to be admitted to ready queue
2. Midterm scheduler
Temporarily removes processes from main memory and places them on secondary memory
3. short term scheduler
Decides which of the ready in memory processes are to be executed.
Q.What are the functions of dispatcher?
Ans: 1.switching context
2. switching to user mode
3.Jumping to the proper location in the user program to restart the program.
Q.What are conditions necessary for deadlock?
Ans: 1.Mutual Exclusion
2.Non Preemption
3.Circular Wait
Q.what are the methods of recovery from deadlock?
ANs: 1.process Termination (it involves either 1. Abort all processes or 2. Abort one process at a time until deadlock cycle is eliminated)
2. resourse Preemption( issues to be addressed include 1.selecting the victim 2.rollback 3. Starvation)
Q. How is a Java file executed ?
Ans: step 1. Static methods are searched
Step 2. Java Vitual Machine uses a class loader to find binary representation of class
Step3 .once the class file is produced The class are linked before it is initialized.
Step 4. Linking
Q.what are the steps involved in linking?
Ans : 1.verification(check loaded representation of class is well formed from symbol table )
2.Preparation(involves allocation of static storage)
3.Resolution (process of checking symbolic references from the test ot other classes)
Q Name an error that is caused during Linking?
Ans Out of memory error
Q what are differences between new and malloc?
ANs: malloc requires special type casting which new does not need.
New required delete to free memory and incase of malloc freeing of memory is done by free keyword.
Q.what is task of formal technical review?
Ans: it focuses on technical correctness of config object that has been modified.
IT also reviews the SCI to determines consistency with other SCI s .
Q.what are steps to configure TOMCAT server?
Ans: step 1.Install Java(set path after running setup)
Step 2.Unzip Tomcat( port change )
Step 3. Download Eclipse(or anyother editor and install it )
Step 4. Test Server.
THE FOLLOWING SETS OF QUESTIONS WHICH ARE GIVEN BELOW WILL HELP YOU TO CLEAR ANY INTERVIEW OF ANY TECHNICAL LEVEL.APART FROM THIS MAKE SURE THAT U HAVE ALREADY READ THE TWO INTERVIEW QUESTIONS I HAD ALREADY UPLOADED OF PERSISTENT AND BIRLASOFT .
============================================UDDALAK BANERJEE(UBJ),CSE ,NIT RAIPUR .
Q.WHAT IS A RESULTSET ?
ANS:IT IS AN INTERFACE IN JAVA which is used to store data on execution of query.
Q.What is white box testing?
Ans:IT is close examination of procedural detail.
Q.what is alpha testing?
Ans: IT is conducted at developer’s site by end users.
It is conducted in controlled environment.
Q.What is beta testing?
Ans:IT is conducted at enduser sites.
Developer is not present here.
Q.what is blackbox testing?
Ans:Examines some fundamental aspects of a system with little regard for the internal logical software of the software.
Q what are DiskScheduling methods?
Ans: FCFS
SSTF
SCAN
LOOK
Q.what is critical section problem?
Ans: TO design a protocol that the processes can use to cooperate.
Critical section is segment of code in which process may be changing common variables,updating tables etc
QWhat is the solution to critical section problem?
Ans: 1.Mutual Exclusion
2.Progress Requirement
3.Bounded Waiting
Q.write PreOrder,postoder and inorder Traversal of the following tree.
A,B,C,D,E ,F,G,H,I
ANS: PREORDER: A B D G C E H I F
POSTORDER: G D B H I E F C A
INORDER: D G B A H E I C F
Q what are the orders of traversal ?
Ans: Post Order: Left Right Root
INorder: Left Root Right
Preorder: Root left right
Q.What is ALOHA?
ANS: IT is earliest random access method(in early 1970s)
It is of two types-
1.Pure ALOHA
2.Slotted ALOHA
Q.what is thoroughput for pure ALOHA?
Ans:S=g* e^-2g
Where
Smax=0.184
When G=0.5
Vulnerable time=2*Tfr
Q.what is throughput for slotted ALOHA?
Ans: S=g*e^-g
Smax=0.368
G=1
Vulnerable time=Tfr
Q.what is SNR?
Ans: It is called Signal to Noise Ratio
Snr= AVERAGE SIGNAL POWER/AVERAGE NOISE POWER
Q what are networking commands in LINUX?
Ans: LYNX --- browse from ordinary terminal
DU---- DISK USAGE OF FILES AND DIRECTORIES IN FILENAME
WHO AM I – RETURN USERNAME
TALK USERNAME--- LETS CONVERSATION WITH OTHER USER
WRITE USERNAME--- EXCHANGE ONLINE MESSAGES
FF---- FINDS FILENAME ON SYSTEM
GREP STRING,FILENAME----- LOOKS FOR STRING IN FILENAME
RLOGIN HOSTNAME--- CONNECTS TO REMOTE HOST
Q.WHAT ARE Java Server Faces specification?
Ans: Packages are:
Javax.faces
Javax.faces.convert------- interfaces defining converter
Javax.faces.event---------interfaces define event file
Javax.faces.webapp------classes required for integration of java server file.
Q.what is full form of ICAD?
Ans: Internet Content Adapter Protocol.
Q.Write a simple if loop in linux?
Ans: echo $ ubj=:uddalak banerjee”
If [ -z “$ ubj”]
Myname= ‘ who am I ‘
Fi
Q. What is Unit testing?
ANs :IT focuses verification effort on the smallest unit of software design—the software components of modules.
Boundary testing is one of the most important unit testing tasks
Unit tests should uncover errors such as the following :
1.comparison of different datatypes
2.incorrect logical operator or precedence
3.incorrect comparison of variables
4.improper loop termination.
Q. What are the disadvantages of water fall model?
ANs: 1.Real Life Projects donot follow sequential flow
2.Customer has to state all requirements first
Q.what are the advantages of spiral model?
ANs: 1.realistic approach
2.Uses prototypes as risk reduction.
Q.what is data transformation?
ANs: Data is transformed into other forms appropriate for mining.
Data transformation involves—
1.smoothing
2.Aggregation
3.Generalization
4.Normalization
5.Attribute Construction
Q What are different Datamodels?
ANs 1.semistructured
2.Object Oriented
3. object relational
4.ER
Q.what are types of Databases?
Ans 1.temporal
2.Sequence Database
3.time series Database
4.Spatial Database
5.Spatial Temporal Database
6.Text Database
7.Multimedia Database
Q. What are techniques used to remove noise?
Ans : 1.Binning
2.Regression
3.Clustering
Q.what is Build?
ANs: Process of converting source code into executable code given to testing
Q.what is change control?
Ans:Change Management Process involves technical change analysis .Cost Benefit analysis and change tracking.
Q.What are key factors considered by a board in making decisions on change?
ANs: 1.size of change
2. complexity of change
3. related systems
4.data when it is needed
5.impact on current and subsequent work
6.cost
7.possible alternatives
Q.what is SCM STANDARD?
ANS: ANSI IEEE 823-1983-1042-1028
Q.What Is demand paging?
ANs: O S copies a diskpage into physical memory only if an attempt is made to access it ( that is if page fault occurs)
Q.WHAT ARE THE DISADVANTAGES OF DEMAND PAGING?
ANS: 1.MEMORY MANAGEMENT with page replacement algorithm becames more challenging
2.Individual programs face extra latency
Q. what is a dispatcher?
Ans:1.Long term scheduler
Decides which job to be admitted to ready queue
2. Midterm scheduler
Temporarily removes processes from main memory and places them on secondary memory
3. short term scheduler
Decides which of the ready in memory processes are to be executed.
Q.What are the functions of dispatcher?
Ans: 1.switching context
2. switching to user mode
3.Jumping to the proper location in the user program to restart the program.
Q.What are conditions necessary for deadlock?
Ans: 1.Mutual Exclusion
2.Non Preemption
3.Circular Wait
Q.what are the methods of recovery from deadlock?
ANs: 1.process Termination (it involves either 1. Abort all processes or 2. Abort one process at a time until deadlock cycle is eliminated)
2. resourse Preemption( issues to be addressed include 1.selecting the victim 2.rollback 3. Starvation)
Q. How is a Java file executed ?
Ans: step 1. Static methods are searched
Step 2. Java Vitual Machine uses a class loader to find binary representation of class
Step3 .once the class file is produced The class are linked before it is initialized.
Step 4. Linking
Q.what are the steps involved in linking?
Ans : 1.verification(check loaded representation of class is well formed from symbol table )
2.Preparation(involves allocation of static storage)
3.Resolution (process of checking symbolic references from the test ot other classes)
Q Name an error that is caused during Linking?
Ans Out of memory error
Q what are differences between new and malloc?
ANs: malloc requires special type casting which new does not need.
New required delete to free memory and incase of malloc freeing of memory is done by free keyword.
Q.what is task of formal technical review?
Ans: it focuses on technical correctness of config object that has been modified.
IT also reviews the SCI to determines consistency with other SCI s .
Q.what are steps to configure TOMCAT server?
Ans: step 1.Install Java(set path after running setup)
Step 2.Unzip Tomcat( port change )
Step 3. Download Eclipse(or anyother editor and install it )
Step 4. Test Server.
Life is a differentiation of dreams which is in terms of education multiplied with effort and innovation
Monday, April 12, 2010
PERSISTENT INTERVIEW
THIS IS AGAIN A DIRECT COMMENTARY VERSION OF THE INTERVIEW WHICH I TOOK FOR PERSISTENT.ALL JUNIORS OR READERS WHO WILL BE READING THIS DOCUMENT WOULD I HOPE STAND TO GAIN FROM THIS EXPERIENCE .I IN MY TIME DID NOT HAVE ANY DIRECT WORD BY WORD UPDATE FROM ANY OF MY SENIORS SO ..I AM UPLOADING FOR ALL OF YOU ..TO HAVE A DIRECT LOOK AT HOW THE INTERVIEW WAS CONDUCTED AND WHAT THE HRS WANT TO KNOW.AND SINCE NOTHING HAS BEEN CHANGED YOU WOULD GET TO FORM YOUR OPINION AND ALSO HELP YOU MENTALLY TO PREPARE FOR THE TEST.ALL THE BEST.
Persistent interview
Persistent interview
Life is a differentiation of dreams which is in terms of education multiplied with effort and innovation
Sunday, April 11, 2010
CS GATE 2006 QUESTION PAPER
Life is a differentiation of dreams which is in terms of education multiplied with effort and innovation
GATE 2008 QUESTION PAPER
IT WAS AGAIN HARD TO GET AND INVOLVED A LOT OF SEARCH..BUT THEN NOW AS I HAVE IT YOU DONT NEED TO PANIC...JUST SIT DOWN AND DIG INTO THE PAPER..PRACTICE..
CS2008
CS2008
Life is a differentiation of dreams which is in terms of education multiplied with effort and innovation
GATE 2007 QUESTION PAPER
THIS WILL PROVIDE A VARIETY IN TERMS OF PRACTICE.THE QUESTION PAPERS FROM 2000-2007 WAS HARD TO GET BUT FINALLY PROCURED THEM.AND NOW I AM UPLOADING THEM...I HOPE THIS WILL PROVIDE ENOUGH OF PRACTICE AND NEGATE THE NEED FOR ANY FURTHER TUTORIALS.
CS-2007
CS-2007
Life is a differentiation of dreams which is in terms of education multiplied with effort and innovation
GATE 2010 QUESTION PAPER
THIS TIME THERE WAS APTI..AND THOSE WHO DID ATTEMPT A LOT ALEAST AROUND 60 MARKS ATLEAST DID WELL UNLIKE THAT IN 2009 WHEN THE QUESTION COMPARATIVELY WAS TOUGHER .
CS-GATE-2010
CS-GATE-2010
Life is a differentiation of dreams which is in terms of education multiplied with effort and innovation
STATISTICS OF GATE
TOTAL NO OF STUDENTS THAT TOOK GATE IN COMPUTER SCIENCE AND ENGG WAS 107000 (1 LAKH 1O THOUSAND APPROX)
UNLIKE OTHER BRANCHES THE TOTAL NUMBER OF STUDENTS APPEARING GATE IN COMPUTERSCIENCE IS DOUBLE AND MORE BECAUSE COMPUTERSCIENCE AND IT ARE TWO FULL FLEDGED BRANCHES WHO TAKE GATE UNDER THE SAME BANNER.iT AND CS ARE ALSO TWO BRANCHES WHICH ARE TAUGHT IN ALMOST ALL ENGINEERING COLLEGES OF INDIA .AT PRESENT THE TOTAL NUMBER OF ENGINEERING COLLEGES IN INDIA IS ABOUT 6700 AND TOTAL NUMBER OF MBA COLLEGES STAND 3300 APPROX.AND THE NUMBER OF COLLEGES IS INCREASING AT A HEALTHY RATE EACH YEAR.
FOR TECHNICAL TRAINING THE PLACES LIKE BANGALORE AND HYDRABAD ARE MOST SUITED BECAUSE OF THE MYRIAD NUMBER OF COLLEGES THAT CROP UP FROM ALL CORNERS OF HYDRABAD AND BANGALORE AND PRESENCE OF HUGE NUMBER OF TRAINING INSTITUTES IN HYDRABAD AND BANGALORE.INCASE ANY JUNIOR READING THIS POST PLEASE OPT FOR YOUR SUMMER TRAINING IN HYDRABAD OR BANGALORE BECAUSE THEY ARE THE PLACES WHICH ARE A HUB OF TECHNOLOGY AND YOU CAN REALLY REALLY LEARN HERE BECAUSE OF THE LARGE NUMBER OF COACHING INSTITUTE WHICH ABOUND HERE SOMEWHAT LIKE KOTA WHERE PEOPLE THRONG FOR IIT JEE PREPARATION.
SO PLEASE MAKE SMALL GROUPS AMOUNG YOURSELVES AND DONT FEEL SHY OR LAZY TO GO THERE FOR TRAINING .IT WOULD PROVE REALLY BENEFICIAL TO YOU IN THE LONG RUN.
UNLIKE OTHER BRANCHES THE TOTAL NUMBER OF STUDENTS APPEARING GATE IN COMPUTERSCIENCE IS DOUBLE AND MORE BECAUSE COMPUTERSCIENCE AND IT ARE TWO FULL FLEDGED BRANCHES WHO TAKE GATE UNDER THE SAME BANNER.iT AND CS ARE ALSO TWO BRANCHES WHICH ARE TAUGHT IN ALMOST ALL ENGINEERING COLLEGES OF INDIA .AT PRESENT THE TOTAL NUMBER OF ENGINEERING COLLEGES IN INDIA IS ABOUT 6700 AND TOTAL NUMBER OF MBA COLLEGES STAND 3300 APPROX.AND THE NUMBER OF COLLEGES IS INCREASING AT A HEALTHY RATE EACH YEAR.
FOR TECHNICAL TRAINING THE PLACES LIKE BANGALORE AND HYDRABAD ARE MOST SUITED BECAUSE OF THE MYRIAD NUMBER OF COLLEGES THAT CROP UP FROM ALL CORNERS OF HYDRABAD AND BANGALORE AND PRESENCE OF HUGE NUMBER OF TRAINING INSTITUTES IN HYDRABAD AND BANGALORE.INCASE ANY JUNIOR READING THIS POST PLEASE OPT FOR YOUR SUMMER TRAINING IN HYDRABAD OR BANGALORE BECAUSE THEY ARE THE PLACES WHICH ARE A HUB OF TECHNOLOGY AND YOU CAN REALLY REALLY LEARN HERE BECAUSE OF THE LARGE NUMBER OF COACHING INSTITUTE WHICH ABOUND HERE SOMEWHAT LIKE KOTA WHERE PEOPLE THRONG FOR IIT JEE PREPARATION.
SO PLEASE MAKE SMALL GROUPS AMOUNG YOURSELVES AND DONT FEEL SHY OR LAZY TO GO THERE FOR TRAINING .IT WOULD PROVE REALLY BENEFICIAL TO YOU IN THE LONG RUN.
Life is a differentiation of dreams which is in terms of education multiplied with effort and innovation
INTERVIEW AT BIRLA SOFT
IT IS A REAL LIFE EXPERIENCE BASED COMMENTRY MODE INTERVIEW.THIS SHOULD HELP ALL JUNIORS AND VIEWERS WHO ARE PREPARING FOR BIRLASOFT OR EQUIVALENT COMPLETELY TECHNICAL LOW RECRUITING CS COMPANIES.
INTERVIEW AT BIRLA SOFT
INTERVIEW AT BIRLA SOFT
Life is a differentiation of dreams which is in terms of education multiplied with effort and innovation
GATE QUESTION PAPER FOR PRACTICE ..
Life is a differentiation of dreams which is in terms of education multiplied with effort and innovation
HOW TO ADD PDF FILES TO A BLOG
WATCH OUT THE FOLLOWING VEDIO AND YOU WOULD KNOW HOW.... VEDIO
Life is a differentiation of dreams which is in terms of education multiplied with effort and innovation
Gate Question Paper 2009
Life is a differentiation of dreams which is in terms of education multiplied with effort and innovation
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